2299. Strong Password Checker II — Daily Problem
Beat 100% of users on execution time. Not much to say about this problem except for one bit manipulation technique.
My Code
class Solution:
def strongPasswordCheckerII(self, password: str) -> bool:
flag1 = flag2 = flag3 = flag4 = 1
ret = None
for i in password:
if ret == i:
return False
if i.isdigit():
flag1 = 0
elif i.isupper():
flag2 = 0
elif i.islower():
flag3 = 0
else:
flag4 = 0
ret = i
if sum([flag1, flag2, flag3, flag4]) == 0 and len(password) >= 8:
return True
return FalseBit Manipulation Code
Method 1: Simulation + Bit Manipulation
Based on the problem description, we simulate the process of checking whether a password meets the requirements.
First, check if the password length is less than 8 — if so, return False.
Then use a bitmask mask to track whether the password contains lowercase letters, uppercase letters, digits, and special characters. Traverse the password: for each character, first check if it's the same as the previous one — if so, return False. Then update mask based on the character type.
Finally, check whether mask == 15 — if so, return True, otherwise return False.
class Solution:
def strongPasswordCheckerII(self, password: str) -> bool:
if len(password) < 8:
return False
mask = 0
for i, c in enumerate(password):
if i and c == password[i - 1]:
return False
if c.islower():
mask |= 1
elif c.isupper():
mask |= 2
elif c.isdigit():
mask |= 4
else:
mask |= 8
return mask == 15Author: ylb
Link: https://leetcode.cn/problems/strong-password-checker-ii/solutions/2068878/by-lcbin-hk2a/
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